Optimal. Leaf size=211 \[ \frac{\sqrt{a^2+2 a b x+b^2 x^2} \left (4 a d e+4 b c d-b e^2\right ) \tanh ^{-1}\left (\frac{2 d x+e}{2 \sqrt{d} \sqrt{c+d x^2+e x}}\right )}{8 d^{3/2} (a+b x)}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+d x^2+e x} (4 a d+2 b d x+b e)}{4 d (a+b x)}-\frac{a \sqrt{c} \sqrt{a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac{2 c+e x}{2 \sqrt{c} \sqrt{c+d x^2+e x}}\right )}{a+b x} \]
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Rubi [A] time = 0.221434, antiderivative size = 211, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.158, Rules used = {1000, 814, 843, 621, 206, 724} \[ \frac{\sqrt{a^2+2 a b x+b^2 x^2} \left (4 a d e+4 b c d-b e^2\right ) \tanh ^{-1}\left (\frac{2 d x+e}{2 \sqrt{d} \sqrt{c+d x^2+e x}}\right )}{8 d^{3/2} (a+b x)}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+d x^2+e x} (4 a d+2 b d x+b e)}{4 d (a+b x)}-\frac{a \sqrt{c} \sqrt{a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac{2 c+e x}{2 \sqrt{c} \sqrt{c+d x^2+e x}}\right )}{a+b x} \]
Antiderivative was successfully verified.
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Rule 1000
Rule 814
Rule 843
Rule 621
Rule 206
Rule 724
Rubi steps
\begin{align*} \int \frac{\sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{x} \, dx &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \frac{\left (2 a b+2 b^2 x\right ) \sqrt{c+e x+d x^2}}{x} \, dx}{2 a b+2 b^2 x}\\ &=\frac{(4 a d+b e+2 b d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{4 d (a+b x)}-\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \frac{-8 a b c d-b \left (4 a d e+b \left (4 c d-e^2\right )\right ) x}{x \sqrt{c+e x+d x^2}} \, dx}{4 d \left (2 a b+2 b^2 x\right )}\\ &=\frac{(4 a d+b e+2 b d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{4 d (a+b x)}+\frac{\left (2 a b c \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \frac{1}{x \sqrt{c+e x+d x^2}} \, dx}{2 a b+2 b^2 x}+\frac{\left (b \left (4 b c d+4 a d e-b e^2\right ) \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \frac{1}{\sqrt{c+e x+d x^2}} \, dx}{4 d \left (2 a b+2 b^2 x\right )}\\ &=\frac{(4 a d+b e+2 b d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{4 d (a+b x)}-\frac{\left (4 a b c \sqrt{a^2+2 a b x+b^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{2 c+e x}{\sqrt{c+e x+d x^2}}\right )}{2 a b+2 b^2 x}+\frac{\left (b \left (4 b c d+4 a d e-b e^2\right ) \sqrt{a^2+2 a b x+b^2 x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{4 d-x^2} \, dx,x,\frac{e+2 d x}{\sqrt{c+e x+d x^2}}\right )}{2 d \left (2 a b+2 b^2 x\right )}\\ &=\frac{(4 a d+b e+2 b d x) \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{c+e x+d x^2}}{4 d (a+b x)}+\frac{\left (4 b c d+4 a d e-b e^2\right ) \sqrt{a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac{e+2 d x}{2 \sqrt{d} \sqrt{c+e x+d x^2}}\right )}{8 d^{3/2} (a+b x)}-\frac{a \sqrt{c} \sqrt{a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac{2 c+e x}{2 \sqrt{c} \sqrt{c+e x+d x^2}}\right )}{a+b x}\\ \end{align*}
Mathematica [A] time = 0.202133, size = 149, normalized size = 0.71 \[ \frac{\sqrt{(a+b x)^2} \left (\left (4 a d e+4 b c d-b e^2\right ) \tanh ^{-1}\left (\frac{2 d x+e}{2 \sqrt{d} \sqrt{c+x (d x+e)}}\right )+2 \sqrt{d} \left (\sqrt{c+x (d x+e)} (4 a d+b (2 d x+e))-4 a \sqrt{c} d \tanh ^{-1}\left (\frac{2 c+e x}{2 \sqrt{c} \sqrt{c+x (d x+e)}}\right )\right )\right )}{8 d^{3/2} (a+b x)} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.244, size = 214, normalized size = 1. \begin{align*} -{\frac{{\it csgn} \left ( bx+a \right ) }{8} \left ( 8\,\sqrt{c}{d}^{5/2}\ln \left ({\frac{2\,c+ex+2\,\sqrt{c}\sqrt{d{x}^{2}+ex+c}}{x}} \right ) a-4\,{d}^{5/2}\sqrt{d{x}^{2}+ex+c}xb-8\,{d}^{5/2}\sqrt{d{x}^{2}+ex+c}a-2\,{d}^{3/2}\sqrt{d{x}^{2}+ex+c}be-4\,{d}^{2}\ln \left ( 1/2\,{\frac{2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e}{\sqrt{d}}} \right ) ae-4\,\ln \left ( 1/2\,{\frac{2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e}{\sqrt{d}}} \right ) bc{d}^{2}+\ln \left ({\frac{1}{2} \left ( 2\,\sqrt{d{x}^{2}+ex+c}\sqrt{d}+2\,dx+e \right ){\frac{1}{\sqrt{d}}}} \right ) bd{e}^{2} \right ){d}^{-{\frac{5}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{d x^{2} + e x + c} \sqrt{{\left (b x + a\right )}^{2}}}{x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 6.14859, size = 1581, normalized size = 7.49 \begin{align*} \left [\frac{8 \, a \sqrt{c} d^{2} \log \left (\frac{8 \, c e x +{\left (4 \, c d + e^{2}\right )} x^{2} - 4 \, \sqrt{d x^{2} + e x + c}{\left (e x + 2 \, c\right )} \sqrt{c} + 8 \, c^{2}}{x^{2}}\right ) -{\left (4 \, b c d + 4 \, a d e - b e^{2}\right )} \sqrt{d} \log \left (8 \, d^{2} x^{2} + 8 \, d e x - 4 \, \sqrt{d x^{2} + e x + c}{\left (2 \, d x + e\right )} \sqrt{d} + 4 \, c d + e^{2}\right ) + 4 \,{\left (2 \, b d^{2} x + 4 \, a d^{2} + b d e\right )} \sqrt{d x^{2} + e x + c}}{16 \, d^{2}}, \frac{4 \, a \sqrt{c} d^{2} \log \left (\frac{8 \, c e x +{\left (4 \, c d + e^{2}\right )} x^{2} - 4 \, \sqrt{d x^{2} + e x + c}{\left (e x + 2 \, c\right )} \sqrt{c} + 8 \, c^{2}}{x^{2}}\right ) -{\left (4 \, b c d + 4 \, a d e - b e^{2}\right )} \sqrt{-d} \arctan \left (\frac{\sqrt{d x^{2} + e x + c}{\left (2 \, d x + e\right )} \sqrt{-d}}{2 \,{\left (d^{2} x^{2} + d e x + c d\right )}}\right ) + 2 \,{\left (2 \, b d^{2} x + 4 \, a d^{2} + b d e\right )} \sqrt{d x^{2} + e x + c}}{8 \, d^{2}}, \frac{16 \, a \sqrt{-c} d^{2} \arctan \left (\frac{\sqrt{d x^{2} + e x + c}{\left (e x + 2 \, c\right )} \sqrt{-c}}{2 \,{\left (c d x^{2} + c e x + c^{2}\right )}}\right ) -{\left (4 \, b c d + 4 \, a d e - b e^{2}\right )} \sqrt{d} \log \left (8 \, d^{2} x^{2} + 8 \, d e x - 4 \, \sqrt{d x^{2} + e x + c}{\left (2 \, d x + e\right )} \sqrt{d} + 4 \, c d + e^{2}\right ) + 4 \,{\left (2 \, b d^{2} x + 4 \, a d^{2} + b d e\right )} \sqrt{d x^{2} + e x + c}}{16 \, d^{2}}, \frac{8 \, a \sqrt{-c} d^{2} \arctan \left (\frac{\sqrt{d x^{2} + e x + c}{\left (e x + 2 \, c\right )} \sqrt{-c}}{2 \,{\left (c d x^{2} + c e x + c^{2}\right )}}\right ) -{\left (4 \, b c d + 4 \, a d e - b e^{2}\right )} \sqrt{-d} \arctan \left (\frac{\sqrt{d x^{2} + e x + c}{\left (2 \, d x + e\right )} \sqrt{-d}}{2 \,{\left (d^{2} x^{2} + d e x + c d\right )}}\right ) + 2 \,{\left (2 \, b d^{2} x + 4 \, a d^{2} + b d e\right )} \sqrt{d x^{2} + e x + c}}{8 \, d^{2}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{c + d x^{2} + e x} \sqrt{\left (a + b x\right )^{2}}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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